Astroart Forum

Hi Rudi, I don't think this is difficult to calculate. If we consider the values of FWHMy and FWHMx as sin (alpha) and cos (alpha) the "alpha" angle is given by: alfa = arctang (sin (alpha) / cos (alpha)) If I understand correctly how the x and y heats of the FWHM are calculated it should be like th...

Hi Rudi, I also have / had your problem because I often shoot more than 1000 or 1500 frames. The option to do everything manually is not the best thing. But I also really liked the "subframeselector". So, I have studied and researched a lot and in the end I proceed in this way ... First of all I eva...